cassandra的命令:
connect <hostname>/<port> (<username> '<password>')?; Connect to thrift service. use <keyspace> [<username> 'password']; Switch to a keyspace. describe keyspace (<keyspacename>)?; Describe keyspace. exit;quit;
describe cluster; Display information about cluster.
show cluster name; Display cluster name. show keyspaces; Show list of keyspaces. show api version; Show server API version. create keyspace <keyspace> [with <att1>=<value1> [and <att2>=<value2> ...]]; update keyspace <keyspace> [with <att1>=<value1> [and <att2>=<value2> ...]]; create column family <cf> [with <att1>=<value1> [and <att2>=<value2> ...]]; update column family <cf> [with <att1>=<value1> [and <att2>=<value2> ...]]; drop keyspace <keyspace>; Delete a keyspace. drop column family <cf>; Delete a column family. get <cf>['<key>']; Get a slice of columns. get <cf>['<key>']['<super>']; Get a slice of sub columns. get <cf> where <column> = <value> [and <column> > <value> and ...] [limit int]; get <cf>['<key>']['<col>'] (as <type>)*; Get a column value. get <cf>['<key>']['<super>']['<col>'] (as <type>)*; Get a sub column value. set <cf>['<key>']['<col>'] = <value> (with ttl = <secs>)*; Set a column. set <cf>['<key>']['<super>']['<col>'] = <value> (with ttl = <secs>)*; Set a sub column. del <cf>['<key>']; Delete record. del <cf>['<key>']['<col>']; Delete column. del <cf>['<key>']['<super>']['<col>']; Delete sub column. count <cf>['<key>']; Count columns in record. count <cf>['<key>']['<super>']; Count columns in a super column. truncate <column_family>; Truncate specified column family. assume <column_family> <attribute> as <type>; Assume a given column family attributes to match a specified type. consistencylevel as <level>; Change the consistency level for set,get, and list operations. list <cf>; List all rows in the column family. list <cf>[<startKey>:]; List rows in the column family beginning with <startKey>. list <cf>[<startKey>:<endKey>]; List rows in the column family in the range from <startKey> to <endKey>. list ... limit N; Limit the list results to N.